How do i do perimeter of irregular shapes?

here's an example:
!

Well, because this is a parallelogram, the sides opposite from each other are equal. So we know that the 2 short sides measure 6 , and also that the diameter of that semicircle circle is 6.

By knowing the diameter of the circle, we can figure out the circumference of the circle using the formula C= 2 x Pi x radius.

Once you have the circumference, divide it in half ( because its a half circle) and add that measurement to the perimeter of the parallelogram :

Circumference ( 1/2) + 6 + 6 + 14 + 14 = total perimeter :)

I hope this helped, I can try draw a picture if you need more assistance :)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

no he doesnt because "-16' is negatiive

step-by-step explanation: