The length of a rectangle is six times the width. to express the length and the width in terms of the same variable, let w be the width. then the length is ?

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

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step-by-step explanation:

add the time and multiply by 2

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