Sketch the graph of y= 2(x-2)^2 +5 and identify the axis of symmetry.

x = 2

Step-by-step explanation:

use the Vertex form, Y=a(x-h)^2+k, to determine the values of a, h, and k.

a=2

h=2

k=5

since the values of a are positive the parabola opens up

Find the vertex (h,k)

(2,5)

Find p from the vertex and the focus

1/8

find the focus

(2,41/8)

Find the axis of symmetry by finding the line that passes though the Vertex and the focus

x=2

Or also a line that goes through the middle but that is just my opinion!