In how many different ways can a committee of 5 people be chosen from a group of 18?

8568

Step-by-step explanation:

You have to choose 5 out of 18, and the order does not matter. So you're looking for the number of combinations, not permutations.

So you have to find 18C5.

nCr = n!/(n-r)!r!

so 18C5 = 18!/13!5!

              = (18 * 17 * 16 * 15 * 14 * 13!)/ 13!5!

              = 18*17*16*15*14/5*4*3*2*1

              = 8568

Hope it helps :)

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation: