Which equation has a graph that is a parabola with a vertex at (–2, 0)?
answer is:
c. y=(x-2)^2

The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.

If the function has a positive leading coefficient, the vertex corresponds to the minimum value.

If it has a negative leading coefficient,  the vertex corresponds to the maximum valuevalue

If the vertex is located at

(–2, 0)

The possibilities are

y =  (x-2)^2

or,

y = - (x-2)^2

Since the problem tells us the answer, we adopt the positive values

y =  (x-2)^2

See attached picture

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3