In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games?

  7 ways (y wins 4 of them)

Step-by-step explanation:

Possibilities are ...

{x, y, y, y} — y wins

{x, y, y, x, x, x} — x wins

{x, y, y, x, y, y} — y wins

{x, y, y, x, x, y, x} — x wins

{x, y, y, x, x, y, y} — y wins

{x, y, y, x, y, x, x} — x wins

{x, y, y, x, y, x, y} — y wins

b

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b