Can someone me! today is my last will mark brainliest

bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

here is his solution:
cos⁡x=16/20
x=cos^(-1)⁡(16/20)=36.8698976≈37°

bob made a mistake in his work. explain the mistake and write the correct solution.

The given triangle is a right-angled triangle. This means that special trig identities can be applies

These identities are as follows:

sin (theta) = opposite / hypotenuse

cos (theta) = adjacent / hypotenuse

tan (theta) = opposite / adjacent

Now, for the unknown theta in the triangle:

The opposite side is 16 and the hypotenuse is 20

This means that we will use the sin not the cos as Bob did

The solution will be as follows:

sin (theta) = opposite / hypotenuse

sin (theta) = 16 / 20

theta = sin^-1(16/20)

theta = 53.13°

Hope this helps :)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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