One mole of a chemical element contains approximately 6.02 × 1023 atoms. how many atoms are present in 4.6 × 104 moles of oxygen? represent the answer in scientific notation. round so the first factor goes to the hundredths place.
a.
2.77 × 10^27 atoms
b.
2.77 × 10^28 atoms
c.
27.7 × 10^27 atoms
d.
27.7 × 10^28 atoms

B. 2.77 · 10^28

Step-by-step explanation:

The total number of atoms is ...

(6.02·10^23 atoms/mol)·(4.6·10^4 mol) = (6.02·4.6)·10^(23+4) atoms

≈ 27.7·10^27 atoms

≈ 2.77·10^28 atoms . . . . . . put in scientific notation form

_____

Scientific notation has one non-zero digit to the left of the decimal point and the exponent adjusted accordingly.

__

Your calculator can help you figure this out. If necessary, put the display into scientific notation mode. (For numbers this size, it is usually not necessary.)

B.  

Step-by-step explanation:

Given : One mole  of a chemical element contains approximately

Then , the number of atoms present in is given by :-

Using exponents property:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer: idk

step-by-step explanation: