△def is reflected to form △d′e′f′ . the vertices of △def are d(−1,−1) , e′(1,−1) , and f(−1,−6) . the vertices of △p′q′r′ are d′(−1,1) , e′(1,1) , and f′(−1,6) . which reflection results in the transformation of△defto△d′e′f′ ? reflection across the x-axis reflection across the y-axis reflection across y = x reflection across y=−x

Reflection across the x-axis because all y-coordinates for triangle DEF are the opposite for the y-coordinates in triangle D'E'F'.

Triangle DEF is reflected across x -axis.

Step-by-step explanation:

Since, the rule of reflection across x -axis,

The rule of reflection across y -axis,

The rule of reflection across line y = x,

The rule of reflection across y = -x ,

Since, in transformation of the triangle DEF with vertices D(-1,-1) , E(1,-1) and F(-1,-6) into the triangle D′E′F' with vertices D′(-1,1) , E′(1,1) , and F′(-1,6).

The rule of reflection is,

Thus, the triangle DEF is reflected across x -axis.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

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step-by-step explanation: