Aship travels 200 miles due west, then adjusts its course 30° north of west. the ship continues on this course for 30 miles. approximately how far is the ship from where it began?

 or

Step-by-step explanation:

we know that

Applying the law of cosines

In this problem we have

substitute the values

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2