Aline has the equation 4x-3y+9=0. find an equation of a line parallel to this line that has a y-intercept of -1

Step-by-step explanation:

"a y-intercept of -1" means that the line passes thru the point (0, -1).

Solving 4x-3y+9=0 for y is one way to determine the slope, m:

-3y = -4x - 9, and so:

y = (4/3)x + 3.  The slope is 4/3.

Starting with the slope-intercept form of the equation of a str. line,

y = mx + b, we get:

-1 = (4/3)(0) + b.  Then b = -1, and  the equation is y = (4/3)x - 1.

so what is the question

step-by-step explanation: