The velocity of a car was 30m/s when the driver pushed the brake of the car and it stopped after 2 seconds. assume that the acceleration was constant during the braking time. find the acceleration and the distance cut during the braking

the "acceleration" is -15m/s (it's negative because it is slowing down, not speeding up[it might just be a positive 15m/s if it is called deceleration and not acceleration])

Step-by-step explanation:

30m/s (starting speed)/2 (the number of seconds it took to stop from 30m/s

the answer is y = 11.54

hope this : )

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)