Tennis balls with a diameter of 2.5 in. are sold in cans of three. the can is a cylinder. what is the volume of the space in the can that is not occupied by tennis balls? assume the tennis balls touch the can on the sides, top, and bottom.

Using 3.14 for PI.

The radius of a ball and the can is half the diameter = 1.25

The height of the can is the height of 3 diameters = 7.5

Volume of one tennis ball:

4/3 x PI x 1.25^3 = 8.18 cubic inches.

Volume of 3 tennis balls: 3 x 8.18 = 24.54 cubic inches.

Volume of can:

PI x 1.25^2 x 7.5 = 36.80 cubic inches.

Space = 36.80 - 24.54 = 12.26 cubic inches.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743