2point
a football coach is trying to decide: when a team is ahead late in the game
which strategy is better?
• play the "regular" defense
• play a "prevent" defense that guards against long gains but makes short
gains easier
the coach reviews the outcomes of 100 games
win
total
50
regular defense
loss
8
15
42
prevent defense
35
77
50
100
total
23
compare the probability of winning when playing regular defense with the
probability of winning when playing prevent defense. draw a conclusion
based on your results
o
a pwintregular) - 0.35
awiniprevent) - 0.65
conclusion: you are more likely to win by playing prevent de
twin regular -0.35
win prevent) - 0.65
conclusion you are more likely to win by playing
oc. awgular) - 084
conclusion you are more
od ular) -084
yo

P(win|regular) = 0.84

P(win|prevent) = 0.70

Conclusion: You are more likely to win by playing regular defense.

Step-by-step explanation:

Divide the regular defense wins(42) but the total of regular defense (50) and you get 0.84.

Then divide the prevent defense wins(35) by the total of prevent defense(50) and you get 0.70.

Since the regular defense is more than the prevent defense, then you are more likely to win by playing the regular defense. (:

i cant see the graph

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3