If endpoints of the diameter of a circle are (8,-6) and (4, -2), what is the standard form equation of the circle?

(X-6)^2 + (y+4)^2 = 8

Step-by-step explanation:

So the distance between the two points is 4 sqrt(2) by using the distance formula. So the diameter of the circle is 4sqrt(2) and the radius is 2sqrt(2).

Now we have to find the center of the circle, which is (6,-4) by the midpoint formula.

Since the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, we can substitute in h, k, and r.

(X-6)^2+(y+4)^2 = 8

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.