Which function can be used to represent the graphed geometric sequence?

f(x) = 80()
f(x) = 320(
f(x) = 80(4)x – 1
f(x) = 320(4)x – 1

f(x) = 80(1/4 x^x-1) ⇒ first answer

Step-by-step explanation:

* Lets explain the geometric sequence

- In the geometric progression there is a constant ratio between

 each two consecutive numbers

Ex:

5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)

* General term (nth term) of a Geometric Progression:

- U1 = a  ,  U2  = ar  ,  U3  = ar2  ,  U4 = ar3  ,  U5 = ar4

∴ Un = a(r)^n-1, where a is the first term , r is the constant ratio

  between each two consecutive terms  and n is the position of

  the number in the sequence

* In the problem we have 4 answers we will search which one can

 be put in the form a(r)^n-1

- The first answer is 80(1/4 r^x-1)

∵ We can multiply 80 by 1/4 ⇒ 80 × 1/4 = 20

∴ It will be 20(x^x-1) ⇒ the form of the geometric sequence

* The answer is the first answer

idn

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: