The second angle of a triangle is 68 more than the first angle. the third angle is two times the first. find the three angles.

first angle:

second angle:

third angle

let the first angle be a

then

second angle= 68+a

third angle=2a

we know

a+b+c=180 [sum of interior angle of triangle is 180]

a+68+a+2a=180

4a=180-68

a=28

Hence

first angle=28

second angle = 96

third angle =56

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4