Which is the best approximation of the solution shown on the linear-quadratic system graphed below?

The beast approximated solution of the linear-quadratic graph is (-1 , 3)

the second answer

Step-by-step explanation:

* To solve this system of equation accurately

- You must have the equation of the parabola

- You must have the equation of the line

- You will solve them together by substitution method to find

  the points of intersection between the parabola and the line

* But here we will try to find the approximated solution

∵ The point if intersection is between -1 and -2 as

   x-coordinate nearest to -1

∵ The point if intersection is between 2 and 3 as

   y-coordinate nearest to 3

∴ The best solution is (-1 , 3)

* The beast approximated solution of the linear-quadratic graph is (-1 , 3)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?