Solve x^2 + 12x = -20 by completing the square.
add (b/2)^2 to both sides of the equation. the value of (b/2)^2 in this equation

x = - 10, x = - 2

Step-by-step explanation:

Given

x² + 12x = - 20

To complete the square

add (half the coefficient of the x- term )² to both sides

x² + 2(6)x + 6² = - 20 + 6² ← completing the square

(x + 6)² = - 20 + 36 = 16

Take the square root of both sides

x + 6 = ± = ± 4

Subtract 6 from both sides

x = - 6 ± 4, hence

x = - 6 - 4 = - 10 or x = - 6 + 4 = - 2

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068