If "n" is a positive integer divisible by 3 and n is less than or equal to 44, then what is the highest possible value of n?

The highest possible value of n is

Step-by-step explanation:

We know by reading the exercise that ''n'' is a positive integer ⇒

n ∈ IN and n > 0

And that ''n'' is less than or equal to 44 ⇒ n ≤ 44

Finally, ''n'' is divisible by 3.

A possible way to solve this exercise is to list all the integers numbers between 0 and 44 that are divisible by 3 and select the highest one.

The integers numbers in this interval are :

3,6,9,12,15,18,21,24,27,30,33,36,39,42

All this numbers are positive integers lowest or equal to 44 and divisible by 3.

Therefore, the highest ''n'' value is 42.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

step-by-step explanation: