At an amusement park, the probability that a child eats a hot dog and drinks a soda pop is 0.47. the probability that a child eats a hot dog is 0.69 and the probability that a child drinks soda pop is 0.86. what is the probability (rounded to the nearest hundredth) that a child drinks soda pop given that the child has already eaten a hot dog?

hint: p(a|b)=p(a∩b) / p(b)

0.55

0.40

0.32

0.68

option D

0.68

Step-by-step explanation:

Conditional Probability:

Finding the probability of an event given that something else has already happened.

p(A) =  The probability that a child eats a hot dog  = 0.69

p(B) =  The probability that a child drinks soda pop = 0.86

p(A∩B) = The probability that a child eats a hot dog and drinks a soda pop = 0.47

Formula to use

P(A|B) = P(A∩B) / P(A)

          = 0.47 / 0.69

          = 0.68

answer: i don't understand it

step-by-step explanation: sorry

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.