Transform the given quadratic function into vertex form f(x) = quadratic function into vertex form f(x) = quadratic function into vertex form by completing the square. by completing the square.

In the equation 5x^2 +6x +4

a = 5, b = 6 and c = 4

For the vertex form we need to find h:

h = b/2 over a = 6/2 over 5 = 3/5

Now find k:

k = 6 - b^2/4a = 4 - 6^2 / 4(5) = 11/5

Replace h in k in the vertex form formula to get:

5(x +3/5)^2 + 11/5

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0