Rewrite the following standard form quadratic equations as intercept form
6x^2-x-1

Right now our quadratic equation, y=x2+12x+32 is in standard form; We want to get it into vertex form; To do this, ... For our equation, a=1, b=12, and c=32; 'h' and 'k' can also be any real number; Vertex form allows ...

Step-by-step explanation:

Right now our quadratic equation, y=x2+12x+32 is in standard form; We want to get it into vertex form; To do this, ... For our equation, a=1, b=12, and c=32; 'h' and 'k' can also be any real number; Vertex form allows ...

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92