Use the one mean t-interval procedure witht the sample mean, sample size, sample standard devaition, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn.\frac{}{}x=2.0 n=51 s=3.8 confidence level = 95%the 95% confidence interval about \mu is to

0.96 < µ < 3.04

Step-by-step explanation:

We need to construct a 95% confidence interval for the population mean based on the give data:  sample mean (x): 2.0, sample size (n): 51, and sample standard deviation (s): s = 3.8

Since the sample size is greater than 30 (n > 30), we will use the corresponding z-value for the confidence interval.  

The z-value is:  1.96

See the attached photo for the formulas needed, calculations, and the construction of the confidence interval

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

a

step-by-step explanation: