On a single roll of two number cubes, what is the probability of rolling doubles given that the sum is 6

1/6

Step-by-step explanation:

We can make a Punnett square to find number of favourable outcome

so

            cube1

         +

cube2    1          2          3        4          5         6

1            2         3           4        5          6        7      

2            3         4           5        6          7         8    

3            4          5         6        7         8         9

4           5          6          7         8         9         10

5         6           7          8         9        10         11

6           7           8          9         10        11         12

The probability of rolling doubles given that the sum is 6

favourable outcome / number of outcome

 6 / 36

  1 / 6

Letter c i’d say

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!