In the expression (x+y)^8, if x=0.3 and y=0.7 , what is the numerical value of the third term?

  0.01000188

Step-by-step explanation:

The third term is ...

  8C2·x^6·y^2 = 28 x^6 y^2

Putting in the given values for x and y, we get ...

  28·3^6·7^2·10^-8 = 1000188×10^-8 = 0.01000188

8C2 = 8!/(2!·(8-2)!) = 8·7/(2·1) = 28

A. 0.010

Step-by-step explanation: I got this right on Edmentum

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

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