Line q goes through points (-3,3) and (-5,-3). at what point does line q cross the y-axis ?

(0,12)

Step-by-step explanation:

To write the equation of a line, calculate the slope between points (-3,3) and (-5,-3). After, substitute the slope and a point into the point slope form. Then convert to the slope intercept form to identify the y-intercept.

Substitute m = 3 and the point (-3,3) into the point slope form.

This means that it crosses at (0,12) since b - 12 for y=mx+b.

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752