What is the equation of the line that has a slope of 0 and passes through the point (6,-8)

Hello there!

we want to find the equation that passes through the point (6, -8) (where this notation stands for (x,y)) with a slope of 0.

a linear equation has the form y = ax+ b

where a is the slope and b is the intercept.

if a = 0, our equation has the form y = b (has no dependence of x)

so we have a constant equation that passes through the point (6, -8) , this means x = 6 and y = -8, but we know that y is constant:

then y = -8 = b

so our equation is y(x) = -8

answer: a and b

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.