In a town’s study of its stray cats, a sample of stray cats had a mean weight of 7.3 lb. the study had a margin of error of 1.1 lb.
what is the interval estimate for the mean weight of the town’s stray cats in the form (lower limit, upper limit)?

show your work:

(6.2, 8.4)

Step-by-step explanation:

Mean weight of the cats = u = 7.3 lb

Margin of Error = E = 1.1 lb

The interval estimate is calculated by subtracting and adding the margin of error to the mean value as shown below:

( u - E, u + E)

Using the given values, we get:

(7.3 - 1.1, 7.3 + 1.1)

(6.2, 8.4)

Thus, the interval estimate for the mean weight of the town’s stray cats is (6.2, 8.4)

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.