Given a circle with measures of (c, d, and r) and a circle with measures of (c', d', and r'), what is d if c c' = 12 and d' = 0.50?

d = 6 units

Step-by-step explanation:

Circumference of the circle is given by:

where, d is the diameter of the circle.

As per the statement:

Given a circle 1 with measures of (C, d, and r) and a circle 2 with measures of (C', d', and r').

Circumference of a circle(C) 1 with diameter(d) is given by:

              .....[1]

Also, the circumference of a circle (C') 2 with diameter(d') is given as:

Divide equation [1] and [2] we have;

⇒

Substitute the given values and d' = 0.50 then;

Multiply both sides by 0.50 we have;

6 = d

or

d = 6 units

Therefore, the value of d is, 6 units

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

a

step-by-step explanation:

the answer is a