Write the product as a sum or difference.
18cos(29x)cos(17x)
select the correct answer below:

9sin(46x)+9sin(12x)

9sin(46x)−9sin(12x)

9cos(46x)+9cos(12x)

9cos(46x)−9cos(12x)

9cos(46x)+9sin(12x)

9sin(46x)−9cos(12x)

9cos(46x) + 9cos(12x)

Step-by-step explanation:

18cos(29x)cos(17x)

According to Product-Sum identities

cos(α)cos(β)= (1/2)[cos(α+β)+cos(α-β)]

Putting α=29x and  β=17x in Product-Sum identity we get

= 18×(1/2)[cos(29x+17x)+cos(29x-1`7x)]

Dividing 18 by 2 we get 9

= 9[cos(46x)+cos(12x)]

Multiplying 9 with both the terms we get

= 9cos(46x)+9cos(12x)

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

l.jnl.j/n.m,lm,

step-by-step explanation: