Mathematics, 06.12.2019 10:31, fireyking19
Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-5,-8); y=-3x+5
Answers: 2
![\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=-3[x-(-5)] \\\\\\ y+8=-3(x+5)\implies y+8=-3x-15\implies y=-3x-23](/tpl/images/0406/3503/03f98.png)
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