The length of a rectangle is shown below:

if the area of the rectangle to be drawn is 10 square units, where should points c and d be located, if they lie vertically below the line that connects b and a, to make this rectangle?

c(-1, 1), d(1,1)
c(-1, -2), d(1,-2)
c(-1, 5), d(1, 5)
c(-1, -7), d(1, -7)

Second option.

Step-by-step explanation:

As you can see in the graph attached, the lenght of the side AB is 2 units.

The formula for calculate the area of  rectangle is:

Where l is the length and w is the width.

Therefore, if the area of the rectangle to be drawn is 10 square units and you know AB=2 units and CD  lies vertically below BA , then you can solve for the length:

Therefore C and D are located at:

The correct answer is,

Option 2).  C(-1, -2), D(1,-2)

Step-by-step explanation:

It is given that,If the area of the rectangle to be drawn is 10 square units

To find the length of rectangle

From the figure we get length of AB = 2 units

Therefore Area = length * breadth = 10

Therefore length = 10/2 = 5 units

To find the points of C and D

we have B(-1, 3)

The point C is 5 units below the point B

Therefore C(-1, 3-5) = C(-1,-2)

we have A(1, 3)

The point D is 5 units below the point B

Therefore D(1, 3-5) = A(1,-2)

Therefore the correct answer is option 2

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2