Abag contains 10 counters. 6 of them are white. a counter is taken at random and not replaced. a second counter is taken out of the bag at random. calculate the probability that only one of the two counters are white.

Step-by-step explanation:

Given:

There are 10 counters.

6 of the counters are white.

Two counters are drawn one after another without replacement.

To Find:

The probability that only one of the two counters is white

Explanation:

P(Only one of the two counters is white)

= P(white) x P( not white) + P(not white) x p(white)

Solution:

P(Only one of the two counters is white) = 6/10 x 4/9 + 4/10 x 6/9

P(Only one of the two counters is white) = 4/15 + 4/15

P(Only one of the two counters is white) = 8/15

The probability is 8/15

moderators are

i think you would have to divide the money he had saved, which is $2,000 by the time he plans on exercising which is 40 hours, and the answer you get should tell you the answer to your question.