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find all polar coordinates of point p = (9, 75°).

1) (9, 75+360n)

2) (−9, 255+360n)

Step-by-step explanation:

(9, 75) is same as (9, 75 + 360)

so it would be (9, 435)

It can also be expressed as (-9, 75 + 180 degrees)

so (-9,255) degrees

In general, (9,75+360 n) for n≥0 represents half of the possible ways of representing the point : (9,75)  

Answer with explanation:

The Position of Point in two dimensional plane , P=(9,75°)

→The general rule of writing the point (r,Ф) in terms of polar coordinates is,

  x=r cos Ф , y=r sin Ф

The angle between Intial side and terminal side is Acute.

Here, r=9 units

And , Ф=75°

→→Period of Cosine and Sine is 2π.

⇒⇒So,the coordinates of Point will be

 x=9 *cos (2nπ+75°), And ,y=9 *sin (2nπ+75°), where n is any integer.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3