The swimming pool is open when the high temperature is higher than 20^\circ\text{c}20 ? c20, degree, c. lainey tried to swim on monday and thursday (which was 333 days later). the pool was open on monday, but it was closed on thursday. the high temperature was 30^\circ\text{c}30 ? c30, degree, c on monday, but decreased at a constant rate in the next 333 days.

Step by step explanation:

Let d represent the rate of temperature decrease in degrees Celsius per day from Monday to Thursday.  

As temperature decreased at a constant rate in the next 3 days, so the rate of temperature will decrease 3d degree Celsius in 3 days.  

We are told that the pool was open on Monday. The high temperature was on Monday. So the decrease in temperature from Monday to Thursday will be .

We have been given that the swimming pool is open when the high temperature is higher than .

As the pool was closed on Thursday. This means that temperature on Thursday was less than or equal to 20 degree Celsius. We can represent this information in an inequality as:

Therefore, the inequality can be used to determine the rate of temperature decrease in degrees Celsius per day, d, from Monday to Thursday.

1. supplementary angles

2. acd and bcd

step-by-step explanation: