If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h = -16t^2+vt+s, where h is in feet. if the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, it's height h is given by the equation h = -16t^2+64t+12. after how many seconds is the height 72 feet?

The object first reaches 72 feet after 1.5 seconds; it is this height again after 2.5 seconds.

Step-by-step explanation:

To find the amount of time it takes to reach 72 feet, we solve the equation

72 = -16t² + 64t + 12

To solve this, we will set it equal to 0 by subtracting 72 from each side:

72-72 = -16t² + 64t + 12 - 72

0 = -16t² + 64t - 60

Next we will use the quadratic formula to solve this:

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076