Mathematics, 18.10.2019 14:00, lacourboud20005

In a recent year, certain colleges and universities received about $268 million in aid. ten years later, they received about $94 million. find the percent of change. state whether the change is an increase or a decrease.

a.35% decrease
b. 35% increase
c. 65% increase
d. 65% decrease

Answers: 2

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Answers

D) 65% decrease.

I worked it out by: 268 mill - 94 mill (calculating the difference in money)
then divided that by the original 268 mill, to finally get 0.64925

And since the money is decreasing, it is a 65% decrease.

Hope this helps, and I think it should be right - but maybe double check in case :)

answered: electrofy456

d. 65% decrease

Step-by-step explanation:

In the current situation, the colleges and universities received about $268 million in aid.

Ten years later, they received about $94 million.

Decrease in amount is = (268-94) million dollars

= 174 million dollars

The percentage of change with respect to current value is :

$\frac{174}{268}\times100=64.93$ % ≈65%

And since the amount of aid received is decreasing, so this percentage is a decreased value.

The answer is option D.

answered: Guest

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200. after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes 1800 - 6400 which gets you 11,600.

answered: Guest

Answer

1 number

explanation

if we use a graphing calculator, there is only one such number $c\in[0.5,0.75]$ that satisfies the conclusion of the mean value theorem, that is, a number $c\in[0.5,0.75]$ such that

$f'(c) = \dfrac{f(0.75) - f(0.5)}{0.75-0.5},$

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.