The vertices of triangle abc are a(2,3), b(–1,2), and c(3,1). if δdef ∼ δabc and de = 4ab, what is the length of ef? the answers are √10,√17,4√10,4√17

EF = 4BC

BC = sqrt ((3-(-1)^2 +(1-2)^2)

=》 BC = sqrt (4^2 +(-1)^2) = sqrt17

=》 EF = 4BC = 4(sqrt 17)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: