What is the equation of a line that has a slope of -1/2 and contains the point (8, 1) in slope intercept form

y = -(1/2)x + 5

Step-by-step explanation:

The general form for a linear equation in slope-intercept form is  

y = mx + b where m is the slope and b is the y-intercept

Use what we know about our line to solve the rest. By using one of the given points, we have 3 of the 4 variables in the above equation.  Use (8, 1), which is (x, y), and we know that  

m = -1/2

The equation becomes...

1 = -(1/2)(8) + b (now solve for b)

1 = -4 + b  

5 = b

Plug that value into the general form...

y = -(1/2)x + 5

something over 10 so ? /10

step-by-step explanation: