What is the surface area of the composite figure

The answer is 672.

Step-by-step explanation:

To solve this problem, first let's find the surface area of the rectangular prism. To do that, multiply each dimension with each (times 2 | just in case you don't understand [what I'm talking about is down below]).

8 x 8 x 2 = 128

8 x 11 x 2 = 176

8 x 11 x 2 = 176

Then, add of the products together to find the surface area of the rectangular prism.

176 + 176 + 128 = 480

Now, let's find the surface area of the square pyramid. Now, for this particular pyramid, let's deal with the triangles first, then the square. Like we did with the rectangular prism above, multiply each dimension with each other (but dividing the product by 2 | in case you don't understand [what i'm talking about is down below]).

8 x 8 = 64.

64 ÷ 2 = 32.

SInce there are 4 triangles, multiply the quotient by 4 to find the surface area of the total number of triangles (what i'm talking about is down below).

32 x 4 = 128.

Now, let's tackle the square. All you have to do is find the area of the square.

8 x 8 = 64.

To find the surface area of the total square pyramid, add both surface areas.

128 + 64 = 192.

Finally, add both surface areas of the two 3-D shapes to find the surface area of the composite figure.

192 + 480 = 672.

Therefore, 672 is the answer.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

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step-by-step explanation: