Write the equation of the line that is parallelto the graph of y=2/3x+7 and passes through the point (-1 -2)

y+2 = 2/3(x+1)

y= 2/3x - 4/3

Step-by-step explanation:

If we want a line parallel to  y=2/3x+7, it will have the same slope

m = 2/3

We have a point (-1,-2), so we can use point slope form

y-y1 = m(x-x1)

y--2 = 2/3(x--1)

y+2 = 2/3(x+1)

If we want the line in slope intercept form, distribute the slope

y+2 = 2/3 x +2/3

Subtract 2 from each side

y+2-2=2/3x +2/3-2

y = 2/3x +2/3 - 6/3

y= 2/3x - 4/3

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer:

c) the x-coordinate of the center of the circle increases by 3