The probability that the first color is violet and the second is orange, if the first is replaced is?

If the crayons are replaced after they are drawn, the probability of drawing any particular color is 1/7.Also the result of each draw is independent of any previous result. Therefore the solution to the first part of the question is found from:P(violet\ then\ orange)=\frac{1}{7}\times\frac{1}{7}=\frac{1}{49}

If the crayons are not replaced after they are drawn, the probability of drawing violet on the first pick is 1/7. Then there are only six crayons left, so the probability of drawing orange is 1/6. The solution to the second part of the question is found from:

P(violet\ then\ orange)=\frac{1}{7}\times\frac{1}{6}=\frac{1}{42}

Does this help

hi

step-by-step explanation: