Of 750 people surveyed, 330 were male and 640 had cell phones. of those with cell phones, 390 were female. what is the probability that a person surveyed was either male or had a cell phone?
a) 360/750 ≈ 0.48
b) 580/750 ≈ 0.7733
c) 700/750 ≈ 0.9333
d) 720/750 ≈ 0.96

Option d -  720/750 ≈ 0.96                    

Step-by-step explanation:

Given : Of 750 people surveyed, 330 were male and 640 had cell phones. Of those with cell phones, 390 were female.

To find : What is the probability that a person surveyed was either male or had a cell phone?

Solution :

Let M be the number of males i.e. M=330

Let C be the number of cell phones i.e C=640

Total number of people = 750

Of 750 people surveyed, 330 were male

The probability of male is

Of 750 people surveyed, 640 had cell phones

The probability of cell phones is

Of those with cell phones, 390 were female.

i.e. reaming were male so 640-390=250

So, Probability of male and cell phone is

We have to find, the probability that a person surveyed was either male or had a cell phone i.e.

Using formula,

Substitute the values,

Therefore, Option d is correct.

understand that i don't know the answers

will someone answer his question

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.