(9cq) find the distance from the balloon to the soccer fields.

The distance from the balloon to the soccer fields = 3.6 miles ⇒ answer (b)

Step-by-step explanation:

* Let the hot air balloon  at point A , the soccer fields

  at point B and the football field at point C

∵ The measure of the angle of depression to the

   soccer fields is 20° 15'

∴ The measure of angle B = 20° 15'

∵ The measure of the angle of depression to the

   football field is 62° 30'

∴ The measure of angle C = 62° 30'

∵ The sum of measures of the interior angles of any triangle = 180°

∴ The measure of angle A = 180 - (20° 15' + 62° 30') = 97° 15'

* The distance between the balloon and the soccer field

  is represented by the side AB of triangle ABC

- Use the sin Rule to find the length of side AB

∵ a/sin(A) = b/sin(B) = c/sin(C)

- a is the side opposite to angle A, b is the side opposite

 to angle B and c is the side opposite to angle C

∵ AB = c ⇒ opposite to angle C

∵ The distance between the two fields = 4 miles

∴ BC = 4 miles

∵ BC = a ⇒ opposite to angle A

∴ 4/sin(97° 15') = c/sin(62° 30')

∴ c = (4 × sin(62° 30')) ÷ sin(97° 15')

∴ c = 3.6 miles

∴ The distance from the balloon to the soccer fields = 3.6 miles

   answer (b)

correct answer:

b.(19,-2)

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.