Given that the points (-3, 2) and (1, 2) are vertices of a square, what two sets of coordinates could form the other two vertices?

The given points have the same Y value.

Find the distance between the X values -3 to 1 is 4 units.

All sides of a square are the same length so the other points must be 4 units away.

Add 4 units to the Y values:

(-3,2) = (-3,(2+4)) = (-3,6)

(1,2) = (1,(2+4)) = (1,6)

Two other points to make a square could be (-3,6) and (1,6)

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: