Once again text is for min word req the problem is in the image again

Set the two equations to equal each other and solve:

3x-2 = x+2

Subtract x from each side:

2x -2 = 2

Add 2 to each side:

2x = 4

Divide both sides by 2:

x = 4/2 = 2

Now replace x with 2 in one of the equations and solve for y:

y = 3x -2 = 3(2) - 2 = 6-2 = 4

X = 2, Y = 4

(2,4)

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a