What is the slant height x of the square pyramid?

express your answer in radical form.

x =

Step-by-step explanation:

We are given a diagram of a pyramid with a right angled triangle which has °, ° and ° angles an the hypotenuse is .

Since we have a right angled triangle, we can apply sin here:

We know that so we can write it as

So we get the slant height of x = .

The slant height of square pyramid = 4√3 m

Step-by-step explanation:

From the figure we can see a square pyramid with lateral edge 8 m

Also the one angle of face triangle is 60° , therefore the face triangle is an equilateral triangle.

Therefore the base is 8 m

To find the slant height

slant height² = Lateral edge² - (base/2)²

    = 8² - (8/2)² = 8² - 4²

    = 64 - 16 = 48

Slant height = √48 = 4√3 m

Therefore slant height of square pyramid =  4√3 m

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363