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given: circle k(o), m fe =56°, fd=ed, m∠efd=76°
find: m∠efo

62°

Step-by-step explanation:

If mEF=56°, then ∠EOF=56° as central angle subtended on the arc EF.

Consider isosceles triangle FOE (this triangle is isosceles, because OF=OE as radii of the circle k(O)). In this triangle, angles adjacent to the base EF are congruent. Since the sum of the measures of all interior angles in triangle is 180°, then

m∠EFO=m∠OEF=1/2(180°-56°)=62°.

Actually, point D is extra to solve this question.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet