Mathematics, 18.11.2019 11:31, 9Time

List these solids in order from the one with least volume to the one with the greatest volume. a. a cube with edge 5 cm b. a cylinder with radius 4 cm and height 4 cm c. a square pyramid with base edges 6 cm and height 6 cm d. a cone with radius 4 cm and height 9 cm e. a rectangular prism with a 5 cm-by-5 cm base and height 6 cm

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answered: macybarham

The list in order from the one with least volume to the one with the greatest volume is

case C) A square pyramid with base edges 6 cm and height 6 cm

case A) A cube with edge 5 cm

case E) A rectangular prism with a 5 cm-by-5 cm base and height 6 cm

case D) A cone with radius 4 cm and height 9 cm

case B) A cylinder with radius 4 cm and height 4 cm

Step-by-step explanation:

To solve this problem calculate the volume of each solid

case A) A cube with edge 5 cm

The volume of a cube is equal to

$V=b^{3}$

where

b is the length side of the cube

substitute the value

$V=5^{3}=125\ cm^{3}$

case B) A cylinder with radius 4 cm and height 4 cm

The volume of a cylinder is equal to

$V=\pi r^{2} h$

substitute the value

$V=(3.14)(4)^{2} (4)=200.96\ cm^{3}$

case C) A square pyramid with base edges 6 cm and height 6 cm

The volume of a pyramid is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the base

h is the height of the pyramid

Find the area of the base B

$B=6^{2}=36\ cm^{2}$ ----> is a square

substitute the values

$V=\frac{1}{3}(36)(6)=72\ cm^{3}$

case D) A cone with radius 4 cm and height 9 cm

The volume of a cone is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the base

h is the height of the cone

Find the area of the base B

$B=\pi r^{2}=(3.14)(4^{2})=50.24\ cm^{2}$ ----> is a circle

substitute the values

$V=\frac{1}{3}(50.24)(9)=150.72\ cm^{3}$

case E) A rectangular prism with a 5 cm-by-5 cm base and height 6 cm

The volume of a rectangular prism is equal to

V=LWH

substitute the values

$V=(5)(5)(6)=150\ cm^{3}$

therefore

The list in order from the one with least volume to the one with the greatest volume is

case C) A square pyramid with base edges 6 cm and height 6 cm

case A) A cube with edge 5 cm

case E) A rectangular prism with a 5 cm-by-5 cm base and height 6 cm

case D) A cone with radius 4 cm and height 9 cm

case B) A cylinder with radius 4 cm and height 4 cm

answered: Guest

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

x=5

step-by-step explanation:

answered: Guest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

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